Interface ISchedulingRule
- All Known Subinterfaces:
IContainer
,IFile
,IFolder
,IProject
,IResource
,IWorkspaceRoot
- All Known Implementing Classes:
MultiRule
IJobManager.beginRule(ISchedulingRule)
and
IJobManager.endRule(ISchedulingRule)
. The job manager guarantees that
no two jobs with conflicting scheduling rules will run concurrently.
Multiple rules can be applied to a given thread only if the outer rule explicitly
allows the nesting as specified by the contains
method.
Clients may implement this interface.
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Method Summary
Modifier and TypeMethodDescriptionboolean
contains
(ISchedulingRule rule) Returns whether this scheduling rule completely contains another scheduling rule.boolean
isConflicting
(ISchedulingRule rule) Returns whether this scheduling rule is compatible with another scheduling rule.
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Method Details
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contains
Returns whether this scheduling rule completely contains another scheduling rule. Rules can only be nested within a thread if the inner rule is completely contained within the outer rule.Implementations of this method must obey the rules of a partial order relation on the set of all scheduling rules. In particular, implementations must be reflexive (a.contains(a) is always true), antisymmetric (a.contains(b) and b.contains(a) iff a.equals(b), and transitive (if a.contains(b) and b.contains(c), then a.contains(c)). Implementations of this method must return
false
when compared to a rule they know nothing about.- Parameters:
rule
- the rule to check for containment- Returns:
true
if this rule contains the given rule, andfalse
otherwise.
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isConflicting
Returns whether this scheduling rule is compatible with another scheduling rule. Iftrue
is returned, then no job with this rule will be run at the same time as a job with the conflicting rule. Iffalse
is returned, then the job manager is free to run jobs with these rules at the same time.Implementations of this method must be reflexive, symmetric, and consistent, and must return
false
when compared to a rule they know nothing about.This method must return true if calling
contains(ISchedulingRule)
on the same rule also returns true. This is required because it would otherwise allow two threads to be running concurrently with the same rule.- Parameters:
rule
- the rule to check for conflicts- Returns:
true
if the rule is conflicting, andfalse
otherwise.
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